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Antwort:  Berechnen Sie die molare Masse von
                   a)     (NH4)2SO4
                   b)     [Co(H2O)6]Cl2
                   c)      CH3COOH
 

a)
N
        2*14                         = 28
H         2*4*1                        = 8
S         32                             = 32
O        
4 * 16                       = 62
            Summe                     
=130 à M = 130 g/mol

b)
Co
      59                             = 59
H         6*2*1                        = 12
O
         6*16                          = 192
Cl        2 * 35,5                     = 71
            Summe                     
=334 à M = 334g/mol

c)
C
        2*12                          = 24
H         4*1                             = 4
O
         2*16                          = 32
            Summe                     
=70 à M = 70g/mol