Antwort: Berechnen Sie die
molare Masse von
a)
(NH4)2SO4
b)
[Co(H2O)6]Cl2
c)
CH3COOH
a)
N
2*14
=
28
H
2*4*1
=
8
S
32
=
32
O 4
* 16
=
62
Summe =130
à
M = 130
g/mol
b)
Co 59
=
59
H
6*2*1
=
12
O
6*16
=
192
Cl 2
* 35,5
=
71
Summe =334
à
M = 334g/mol
c)
C
2*12
=
24
H
4*1
=
4
O
2*16
=
32
Summe =70
à
M = 70g/mol